Question

Find the common difference of an AP, in which a20 - a16 = 40​

Answer 1

Answer:

common difference on this equation is that 20 and 16 both digits come in the table of 2 and 4.

2×8= 16, 2×10= 20

4×4= 16, 4× 5= 20

Answer 2

The common difference is, 10

Given : In an AP value of, a20 - a16 is 40

To find : The value of common difference of the given AP.

Solution :

We can simply solve this mathematical problem by using the following mathematical process. (our goal is to calculate the common difference)

Let, the first term of AP = a

And, common difference = d

So,

20th term of AP (a20) = a + (20-1) × d = a+19d

16th term of AP (a16) = a + (16-1) × d = a+15d

[Applied formula : nth term of AP = a+(n-1)×d]

According to the data mentioned in the question,

a20 - a16 = 40

(a+19d) - (a+15d) = 40

a+19d-a-15d = 40

4d = 40

d = 10

So, common difference = 10

(This will be considered as the final result.)

Hence, the common difference is 10