Question

find the common difference of an AP whose 26th term is 160 and first term is 10 ​

Answer 1

Answer:

first term (a)=10

and

26th term =160

a+(n-1)d=160 [here d is the common difference]

10+(26-1)d=160

25d=160-10

d=150/25

=6

Therefore, common difference of the A.P. is 6.

Answer 2

SOLUTION

GIVEN

In an AP 26th term is 160 and first term is 10

TO DETERMINE

The common difference

CONCEPT TO BE IMPLEMENTED

If in an arithmetic progression

First term = a

Common difference = d

Then nth term of the AP

= a + ( n - 1 )d

EVALUATION

Let common difference = d

Now First term = a = 10

By the given condition

26th term = 160

⇒ a + 25d = 160

⇒ 10 + 25d = 160

⇒ 25d = 150

⇒ d = 6

FINAL ANSWER

The common difference = 6

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