Question

Find the common difference of an AP whose first term is 1/2 and the 8th term is 17/6 . Also write it's 4th term​

Answer 1

a=1/2

$a_{8}$

=17/6

a+7d=17/6

1/2+7d=17/6

(1+14d)/2=17/6

1+14d=17/3

14d=17/3-1

14d=(17-3)/3

14d=14/3

d=1/3

$a_{4}$

a+3d

1/2+3/3

(3+6)/6

9/6

3/2

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Answer 2

Answer:

Step-by-step explanation: 17/6 = 1/2 + 7d

17/6-1/2 = 7d

7/3 = 7d

d = 1/3

a4 = 1/2 + 3*1/3

= 1/2 + 1

= 3/2