Find the common difference of an AP whose first term is 4,the last term is 49
and the sum of all it's term is 265
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)(Answer:
Step-by-step explanation:
a = 4
an = 49
sn = 265
= n/2 (a+l)
= n/2 (53)
265=n/2 (53)
n/2 = 265/53
= 5
: n = 10
an = a+(n-1)d
49 = 4+ (5-1) d
49 = 4+4d
4d= 49-4
4d= 45
d= 45/4
=11.25
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