Find the common difference of an ap whose first trem is 100 and sum of whose firts 6 terms is 5 times the sum of next 6 terms
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Let AP be a, a+d, .. where a = 100, d= d
Sn= a + (n-1)d
100 + 5d
Next 6 terms are
a+6d, a+ 7d.............a+ 11d
Sn = a+ 6d + ( a + 6d+ a+ 11d)
=2a+ 23 d
100+ 5d = 5( 2a+ 23d)
100 + 5 d = 1000+ 23 d
900 = - 18 d
d = -50
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