find the common difference of following AP. 49;41;33;25;...
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Answer:
1,9,17,25,33,41,49,57
Your input 1,9,17,25,33,41,49,57 appears to be an arithmetic sequence
Find the difference between the members
a2-a1=9-1=8
a3-a2=17-9=8
a4-a3=25-17=8
a5-a4=33-25=8
a6-a5=41-33=8
a7-a6=49-41=8
a8-a7=57-49=8
The difference between every two adjacent members of the series is constant and equal to 8
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Hy good morning how are you
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