Question

Find the common difference of the ap: 1/3q,1-6q/3q,1-12q/3q

Answer 1

$Given \: A.P : \frac{1}{3q} , \frac{1-6q}{3q} \:and \\\frac{1-12q}{3q}$

$\red{Common \: Difference (d)} \\= a_{2} - a_{1} \\= \frac{1-6q}{3q} - \frac{1}{3q} \\= \frac{1-6q - 1}{3q} \\= \frac{-6q}{3q} \\= -2$

Therefore.,

$\red{Common \: Difference (d)} \green {= -2}$

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Answer 2

Answer:

Common difference, d = a2 – a1 = \frac{1-6 q}{3 q}-\frac{1}{3 q}

= \frac{1-6 q-1}{3 q}=\frac{-6 q}{3 q} = -2

Step-by-step explanation: