Find the common difference of the ap whose 10th term is 62 and 5th term is 2 plz anyone answer this I want to conform my answer
Answers
Answered by
1
a10=62
a+9d=62
a5=2
a+4d=2
a+9d=62
a+4d=2
Eliminating,
-5d=-60
d=12
a+9d=62
a5=2
a+4d=2
a+9d=62
a+4d=2
Eliminating,
-5d=-60
d=12
shakthi2102:
I am sorry the 5th term is 12 not 2 I made a typing mistake
Answered by
1
Hello friend!!
Rajdeep here.....
Let the first term be a and common difference be d.
10th term = 62
so a + 9d = 62.......(i)
Again, 5th term = 2
so a + 4d = 2........(ii)
or a = 2 - 4d......(iii)
Substituting (iii) on (i),
a + 9d = 62
=> 2 - 4d + 9d = 62
=> 2 + 5d = 62
=> 5d = 60
=> d = 60/5
=> d = 12
Thanks!!
Rajdeep here.....
Let the first term be a and common difference be d.
10th term = 62
so a + 9d = 62.......(i)
Again, 5th term = 2
so a + 4d = 2........(ii)
or a = 2 - 4d......(iii)
Substituting (iii) on (i),
a + 9d = 62
=> 2 - 4d + 9d = 62
=> 2 + 5d = 62
=> 5d = 60
=> d = 60/5
=> d = 12
Thanks!!
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