Question

find the common difference of the AP whose 1st term is 12 nd 5th is 10​

Answer 1

Answer:

$a = 12$

$a + 4d = 10$

$12 + 4d = 10$

$4d = 10 - 12$

$4d = - 2$

$d = \frac{ - 2}{4}$

$d = \frac{ - 1}{2}$

Answer 2

Answer:

d = -1/2

Step-by-step explanation:

1st term of the AP is 12.

=> a = 12.

5th term of the AP is 10.

[nth term of the AP = aₙ = a + (n - 1) * d]

Thus,

a₅ = a + (5 - 1) * d

a₅ = a + 4d

10 = a + 4d

=> 10 = 12 + 4d

=> 10 - 12 = 4d

=> -2 = 4d

=> d = -1/2

Therefore, common difference = -1/2.

Hope it helps!