find the common difference of the AP whose sum of first four terms is 40 and that of fourteen terms is 280
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Answer:
d = 56
Step-by-step explanation:
s4 = 4/2( 2a+3d)=40
s14=14/2(7a+13d)=280
4a+3d=40
14a+13d=280
solve them
d=56
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