Question

Find the common difference of the ap whose sum of 'm' terms is xm^2+ym

Answer 1

Answer:

Step-by-step explanation:

Sn=xm2+ym

S1=a=x(1)+y(1)=x+y

S2=a+a+d=2a+d

=x(2)2+y(2)=4x+2y

(i.e)2(x+y)+d=4x+2y

d=4x+2y−2x−2y

Hence d=2x