Question

find the common difference of the sequence whose 5th term is 30 and 15th term is 60 and also find the first term and 25th term?​

Answer 1

Step-by-step explanation:

a5=a+4d=30

a15=a+14d=60 (or) a+4d+10d=a5+10d=30+10d=60

10d= 30

d=3

a5=30=a+4(3)=a+12

a=30-12=18

a25=a+24d =18+24(3)=18+72=90