Question

find the common difference pf the A.P √3,√12,√27,√48

Answer 1

Converting then first
√3,2√3,3√3…….
d1= 2√3-√3=√3
d2=3√3-2√3=√3
So Common Difference is √3

Answer 2

Answer:

The common difference is $\sqrt{3}$.

Step-by-step explanation:

The given AP is

√3,√12,√27,√48

Simplify each term.

$\sqrt{12}=\sqrt{4\times 3}=2\sqrt{3}$

$\sqrt{27}=\sqrt{9\times 3}=3\sqrt{3}$

$\sqrt{48}=\sqrt{16\times 3}=4\sqrt{3}$

The given AP can be written as

$\sqrt{3},2\sqrt{3},3\sqrt{3},4\sqrt{3}$

The common difference is

$d=a_2-a_1$

$d=2\sqrt{3}-\sqrt{3}=\sqrt{3}$

Therefore the common difference is $\sqrt{3}$.