find the common factor in the given terms 13xy,39x²y
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(13*x*y) = (13xy) [13,x and y are at its irreducible forms.(13 because it is a prime factor)](13*3*x*x*y) = (13xy)(3x) [The number 39 can be expressed as the product of two prime factors, 13 and 3. x square can be expressed as x*x. y is at its irreducible form.]The common factor in both numbers is 13xy.Therefore, 13xy is the common factor.Hope its helpful!
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