Math, asked by GODISHANYT, 6 months ago

Find the common factors of 14 pq, 28p^2 q^2
please I need Corr ect ansew I will give 100 points​

Answers

Answered by iamntg
2

Answer:

14pq= 14× p× q

= 2 × 7 × × p × q

28p²q² = 28× p² × q²

= 2 × 2 × 7 ×p² × q²

= 2× 2 × 7 × p × p × q × q

so,

14pq = 2×7 × p × q

28p²q²= 2× 2 × 7 ×p × p × q × q

HOPE UH LIKE IT...PLZ THANK MY ANSWER ND DO FOLLOW MEH 。◕‿◕。

Similar questions