Find the common factors of 14 pq, 28p^2 q^2
please I need Corr ect ansew I will give 100 points
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Answer:
14pq= 14× p× q
= 2 × 7 × × p × q
28p²q² = 28× p² × q²
= 2 × 2 × 7 ×p² × q²
= 2× 2 × 7 × p × p × q × q
so,
14pq = 2×7 × p × q
28p²q²= 2× 2 × 7 ×p × p × q × q
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