Math, asked by gamingush, 1 year ago

Find the common factors of the given terms.
(1). 12x, 36, (2). 2y, 22xy, (3). 14pq, 28 p square, and q square,
(4). 2x, 3x, 4, (5). 6 abc, 24ab, 12 a square b,
(6). `16 x cube, -4x, 32x, (7). 10pq, 20qr, 30rp,
(8). 3x, y, 10x, y square, 6, x, y square z
I know this is a lot but I need help I will give you many points and also mark you as brainliest.

Answers

Answered by abhay022
5
A.
12x = 2×2×3×(x)
36 = 2×2×3×3
Now common factors = 2×2×3 = 12

B.
2y = 2× (y)
22xy = 2×11×(x)×(y)
Common factors = 2×(y) = 2y

C.
14pq = 2×7×(p)×(q)
28p^2 q^2 = 2×2×7×7×(p×p)×(q×q)
Common factors = 2×7×p×q = 14pq
Do it as I did .. u can get all answer ..
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Answered by battlegaming552
2

Answer:

(i) 12x = 2 × 2 × 3 × x

36 = 2 × 2 × 3 × 3

Common factor = 2 × 3 = 6

(ii) 2y = 2 × y

22y = 2 × 11 × y

Common factor = 2

(iii) 14pq = 2 × 7 × p × q

28p 2q 2 = 2 × 2 × 7 × p × p × q × q

Common factor = 14pq

(iv) 2x = 2 × x

3x 2 = 3 × x × x

4 = 2 × 2

Common factor = 1

(v) 6abc = 6 × a × b × c

24ab 2 = 2 × 2 × 2 × 3 × a × b × b

12a 2b = 2 × 2 × 3 × a × a × b

Common factor = 6ab

(vi) 16x 3 = 2 × 2 × 2 × 2 × x × x × x

− 4x 2 = − 2 × 2 × x × x

32x = 2 × 2 × 2 × 2 × 2 × x

Common factor = 2x

(vii) 10pq = 2 × 5 × p × q

20qr = 2 × 2 × 5 × q × r

30rp = 2 × 3 × 5

Common factor = 2 × 5 = 10

(viii) 3x 2y 3 = 3 × x × x × y × y × y

10x 3y 2 = 2 × 5 × x × x × x × y × y

6x 2y 2z = 2 × 3 × x × x × y × y × z

Common factor = x 2y 2

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