Question

Find the common factors of the given terms:

(i) 12x , 36

(ii) 2y, 22xy (iii) 2x, 3x², 4​

Answer 1

$\red{\sf {Solutions:}}$

$\blue{\sf {1)12x ,36}}$

$\pink{\sf { Answer: \: }}$

$\pink{\sf { \implies \: 12x = 12 \times x}}$

$\pink{\sf { \implies 36 = 12 \times 3}}$

Hence , the common factor in 1st answer is 12.

$\blue{\sf { \: 2) \: 2y, 22xy}}$

$\pink{\sf { Answer: \: }}$

$\pink{\sf { \implies \: \: 2y = 2 \times y}}$

$\pink{\sf { \implies \: \:22xy = 2 \times 11 \times x \times y}}$

Hence , the common factor in 2nd answer is 2

$\blue{\sf { 3) \: 2x, 3x², 4}}$

$\pink{\sf { Answer: \: }}$

$\pink{\sf { \implies \: \: 2x = 2 \times x}}$

$\pink{\sf { \implies \: \: 3x {}^{2} = 3 \times x \times x }}$

$\pink{\sf { \implies \: \: 4 = 2 \times 2 }}$

Hence , we can see there is no common factors than 1 ,

So ,

The common factor is 1 .

Answer 2

$\purple{ \sf here \: are \: your \: answers : }$

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$\sf(i)12x,36 = { \sf \boxed{12} \times x} \: , \: { \boxed{12} \times 3}$

∴ 12 is the common factor in 12x , 36

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$\sf(ii)2y,22xy = \boxed{ 2} \times \boxed{ \sf y} \: , \: \boxed{2} \times \boxed{ \sf y} \times 11 \times x$

∴ 2 , y are the common factors in 2y , 22xy

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$\sf(iii)2x, {3x}^{2} ,4$

$\sf2x = \boxed{1 }\times 2 \times x$

$\sf{3x}^{2} = \boxed{1} \times 3 \times x \times x$

$\sf4 = \boxed{ 1} \times 2 \times 2$

∴ 1 is the common factor in 2x, 3x², 4

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