Question

find the common interest on rupees 10000 for one year at 10% per annum is the interest is compounded half yearly


answer with correct explanation


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Answer 1

Solution ●●●●●●
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Given,

P = ₹ 10000

R = 10% p.a.

T = 1 year

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Now,

$A = P \times (1 + \frac{R}{200} ) {}^{2t} \\ \\ \: \: \: \: = Rs \: 10000 \times (1 + \frac{10}{200} ) {}^{2 \times 1} \\ \\ \: \: \: \: = Rs 10000 \times ( \frac{21}{20} ) {}^{2} \\ \\ \: \: \: \: = Rs \: 10000 \times \frac{21}{20} \times \frac{21}{20} \\ \\ \: \: \: \: \: = Rs \: 11025$

$CI = A - P \\ \\ \: \: \: \: \: \: = Rs \: (11025 - 10000) \\ \\ \: \: \: \: \: \: = Rs \: 1025$