Find the common ratio and the general term of geometric sequence 2,4,8,16
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Answer:
2 and 2^n
Step-by-step explanation:
let a= 2
let common ratio, r = (r2/r1) = (4/2) = 2
general term, tn = ar^(n-1)
tn = 2*2^(n-1)
tn =( 2^1 )*(2^(n-1))
tn = 2^ (1+n-1)
tn = 2^n
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