Find the common ratio of G.P; 2,212,4,.... Show that the sum of multiples of 3 between 1 and 100 is 1683.
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Step-by-step explanation:
Sum = 3 + 6 + 9 + …99
Here a = 3 and d = 3
an = a+(n-1)d = 99
3+(n-1)3 = 99
3n = 99
n = 99/3= 33
Sn = (n/2)(2a+(n-1)d)
= (33/2)(2×3+(33-1)3)
= (33/2)(6+32×3)
= (33/2)×102
= 1683
Hence option
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