Math, asked by lokesh72563, 3 months ago

find the common solution of (X - 7) (x -15 is less than 0 and (x-2) (x-8) (x-2) l is greater than or equal to 0

Answers

Answered by bhaskaranand2009
0

Answer:

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Answered by as28012007
1

Answer:

Step-by-step explanation:

`log_0.5 ((3-x)/(x+2)) lt 0`

Here, `((3-x)/(x+2))` should be greater than `0` as we can not have logarithms of negative values.

`:. (3-x)/(x+2) gt 0`

`=>x !=-2 and x lt 3`

`=> x in (-2,3) ->(1)`

Now, `log_0.5 ((3-x)/(x+2)) lt 0`

`=> (3-x)/(x+2) lt 0^(0.5)`

`=> (3-x)/(x+2) lt 1`

`=> (3-x)/(x+2) - 1 lt 0`

`=> (3-x-x-2)/(x+2) lt 0`

`=>(1-2x)/(x+2) lt 0`

`:. x in (-oo,-2)->(2)`

From (1) and (2), we can see that their is no common value that lies in both intervals.

So, there is no solution available for the given solution.

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