Find the common :
x^2 + 1 + 2x - 16y^2
Answers
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Step-by-step explanation:
Correct option is
A
x+2y+2=0
equation of tangent to the parabola
y
2
=2x is y=mx+
m
2
1
⇒y=mx+
2m
1
_______ (i)
And equation of tangent to the parabola
x
2
=16y is y=mx−4m
2
_________ (ii)
For common tangent, equation (i) and equation (ii) are identical.
∴
2m
1
=−4m
2
⇒m
3
=−
8
1
⇒m=−
2
1
∴ equation of common tangent is
y=−
2
1
x−
2
1
2
1
⇒2y=−x−2
⇒x+2y+2=0
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