find the complement of A'B'C'+A'BC'
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So we need to take the complement of ab+bc′+a′c+abc
(ab+bc’+a’c+abc)’
= (ab)’(bc’)’(a’c)(abc)’
= (a’+b’)(b’+c)(a+c’)(a’+b’+c’)
= (a’b’ + a’c + b’ + b’c)(ab’ + ac’ + a’c’ + b’c’ + c’)
= a’b’c’ + a’b’c’ + a’b’c’ + ab’ + ab’c’ + a’b’c’ + b’c’ + b’c’ + ab’c
Now we remove duplicates and simplify
= a’b’c’ + ab’ + ab’c’ + b’c’ + ab’c
= a’b’c’ + ab’ + b’c’
= ab’ + b’c’
= b’(a+c’)
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