Question

Find the complement of F=P’.Q.R + P.Q’.R.​

Answer 1

Answer:

Dual of P'QR' + PQ'R + P'Q'R:

(P'+Q+R').(P+Q'+R).(P'+Q'+R)

Complement of PQ'R + Q.(P'R' + PR'):

[PQ'R+Q.(P'R'+PR')]'

= (PQ'R)'.[Q.(P'R'+PR')]'

= (P'+Q+R').[P'QR'+PQR']'

= (P'+Q+R').(P+Q'+R).(P'+Q'+R)

Hence proved.

Answer 2

Answer: Complement of F

Explanation:

To find : Complement of F = P'.Q.R + P.Q'.R

F = P'.Q.R + P.Q'.R

F' = R(P'.Q + P.Q')

F' = (P ⊕ Q) R

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