find the complement of xyz'+(xy)'+xy'
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Answer:
(x'+y'+z).(x'+y').(x'+y)
Explanation:
Let a= xyz'+(xy)'+xy'
Complement of a = a' = (xyz'+(xy)'+xy')'
Using laws:
(ab)'= a'+b'
(a+b)'=a'.b'
a' = (xyz'+(xy)'+xy')'
= (xyz')'.(xy).(xy')'
=(x'+y'+z).(x'+y').(x'+y)
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