Question

find the complementary angles if their difference is 13°​

Answer 1

$\boxed{ \tt \underline{GIVEN}}$

$\tt⟿diff. \: between \: complementary \: angles \\ \tt = 13 \degree$

$\boxed{ \tt \underline{FIND}}$

$\tt⟿COMPLEMENTARY \: ANGLES \: ARE ?$

$\boxed{ \tt \underline{SOLUTION}}$

$\tt\rightarrow let \: the \: f1st \: complementary \: angle \: be \: x \degree$

$\tt\rightarrow 2nd\: complementary \: angle \: be \: 90 - x \degree$

$\tt Now, \: we \: know \: that \\ \tt sum \: of \: complemenrary \: angles = 90\degree$

$\tt \longrightarrow x - (90 - x)= 1 3 \degree$

$\tt \longrightarrow x - 90 + x= 13 \degree$

$\tt \longrightarrow 2x - 90 = 13 \degree$

$\tt \longrightarrow 2x = 13 + 90$

$\tt \longrightarrow 2x = 103$

$\tt \longrightarrow x = \frac{ \cancel{103}}{ \cancel2} = 51.5 \degree$

$\tt The \: first \: angle = x = 51.5 \degree$

$\tt Second \: angle = 90 - x = 38.5 \degree$

Answer 2

Answer:

$\huge \underline{ \tt \red{given}}$

DIFFERENCE BETWEEN THE COMPLEMENTARY ANGLES = 13 °

AS , WE KNOW

$\tt \green{sum \: ofcomplementary \: angle = 90 \degree}$

$\tt \red {x - (90 \degree - x) = 13 \degree}$

$\tt \red{x - 90 \degree + x = 13 \degree}$

$\tt \red{2x - 90 \degree = 13 \degree}$

$\tt \red{2x = 13 \degree + 90 \degree}$

$\tt \red{2x = 103 \degree}$

$\tt \green{ \therefore \: x = 51.5 \degree }$

SO ,

THE FIRST ANGLE = 51 . 5 °

SECOND ANGLE = 90 - x = 90 - 51.5° = 38.5°

$\huge \mathfrak{hope \: this \: all \: helps}$