Find the complete integral of 2(2 + ()2) = 1
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Answer:
Given I=∫x2−a21dx
x=asecθ,dx=asecθtanθdθ
x2−a2=atanθ
I=∫atanθasecθtanθdθ
I=∫tanθdθ=ln∣secθ∣+c
I=∫atanθasecθtanθdθ
I=∫secθdθ=ln∣secθ+tanθ∣+c
I=ln(ax+(ax)2−1)+c
I1=∫x2+6x−7dx=∫(x
Step-by-step explanation:
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