Question

Find the complete integral of p2+x2y2q2=x2z2

Answer 1

Answer:

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Answer 2

Answer:

z= (a + x)² + (y-a) /½. (y-ay½ +6.

Step-by-step explanation:

p² + q² = 2² (x + y) — ci

= ( 32 ) + ( 2 · 33 )² = x + y — (ii)

put d² = 2 so that 2 = log zdz

then;

1 J2 = = P(say)

and 22 ½ 3y = Q(say) Z ay sy

Substituting these value in (ii), p² + Q² = x+y p² -x = y-a² = a (say)

i.e, p= √a+z

Now,

dz = Pdx+ Qdy

dz = √a+x dx + √y-a dy

on Integrate;

z= (a + x)² + (y-a) /½. (y-ay½ +6