Find the complex conjugate of 3(7+7i)+i(7+7i)
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Answered by
0
Answer:
3(7+7i) + i(7+7i)= 21+21i + 7i + 7i^2. 21+28i + 7i^2, we know that i^2 =-1. i.e 21+28i +7(-1) = 21+28i-7= 14+28i. The complex conjugate of 14+28i is 14-28i.( To find the complex conjugate, we should change the sign of imaginary part) i.e 14+28i becomes 14-28i. Hence the complex conjugate of given question is 14-28i. Hope this helps you.
Answered by
2
Answer:
14-28i
Step-by-step explanation:
3(7+7i)+i(7+7i)
=21+21i+7i+7i^2
=7i^2+28i+21
=we know that i^2=-1
=-7+21+28i
=14+28i
for finding complex conjugate ,the imaginary part sign changes to either positive to negative or negative to positive
for example,a+ib changes to a-ib
thereforethe solution for given question is
14-28i
i hope this helps u
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