Question

find the complex roots of the equation 2x^2-9x+12=0​

Answer 1

Answer:

$2 {x}^{2} - 9x + 12 = 0 \\ = > x = \frac{ - b± \sqrt{ {b}^{2} - 4ac} }{2a} \\ = > x = \frac{9± \sqrt{ {9}^{2} - 4 \times 2 \times 12} }{2 \times 2} \\ = > x = \frac{9± \sqrt{81 - 96} }{4} \\ = > x = \frac{9± \sqrt{( - 15)} }{4} \\ = > x = \frac{9± \sqrt{15} i}{4}$

Answer 2

Answer:

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