Find the components along the x, y, z axes of the angular momentum of a particle, whose position vector is with components x, y, z and momentum is p with components px, py and pz. Show that if the particle moves only in the x-yplane the angular momentum has only a z-component.
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Answered by
31
we know ,
angular momentum (L) = r x P
where r is the position vector and P is the linear momentum .
a/c to question,
particle moves only in x-y plane .
so,
r = x i + y j
P =Px i +Py j
now,
L = ( x i + yj ) × (Px i + Py j )
=(x.Py k - y.Px k)
=( xPy -y.Px) k
hence, proved that if particle moves in x-y plane then angular momentum of its in z-axis
=
angular momentum (L) = r x P
where r is the position vector and P is the linear momentum .
a/c to question,
particle moves only in x-y plane .
so,
r = x i + y j
P =Px i +Py j
now,
L = ( x i + yj ) × (Px i + Py j )
=(x.Py k - y.Px k)
=( xPy -y.Px) k
hence, proved that if particle moves in x-y plane then angular momentum of its in z-axis
=
Answered by
1
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