Question

Find the components of a force of 150 N into two directions

inclined at angle of 45° and 30° with the force.​

Answer 1

Explanation:

150 cos45 and 150sin 45

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Answer 2

Answer:

The component of force inclined at an angle of 45° and 30° are 106N and 130N.

Explanation:

Given:

A a force of magnitude 150N.

To Find:

Components of the force inclined at an angle of 45° and 30° with the force.​

Solution:

Component of the force inclined at an angle of 45°,

$Fcos45=150*\frac{1}{\sqrt{2} }=75\sqrt{2}=106N$

Component of the force inclined at an angle of 30°,

$Fcos30=150*\frac{\sqrt{3} }{2} =75\sqrt{3}=130N$

Hence, The component of force inclined at an angle of 45° and 30° are 106N and 130N.