find the compound insert on a sum of rupees 20400 when rate is 12% compound annually for 1.1/2 year step by step solutions with formula
Answers
Answered by
0
Answer:
3896
Step-by-step explanation:
P = 20400
R = 12%
T = 1 1/2 years = 18 months
CI = P(1 + r/200)^2t - P
= 20400( 200 + 12/200)^3 - 20400
= 20400 x 212/200 x 212/200 x 212/200
= 102 x 212 x 212/200 x 212/200
= 24,296 - 20400
= ₹ 3896
Similar questions