Find the compound interest 4000 for 3 years at 5%annum
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Rate of Interest(r ) = 10%
Time = 2.5 years Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 4000 (11/10)2
A = 4000 ( 121 / 100 )
A = Rs 4840
The Amount after two years = Rs 4840 Now Principal = Rs 4840
Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242
Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082
C.I = A - P
C.I = Rs 5082 - Rs 4000 = Rs1082
∴ The compound interest is Rs 1082.
Time = 2.5 years Here first we take n = 2 years.
A = P( 1 + r /100)n Where A = Amount and n = number of years
A = 4000 (11/10)2
A = 4000 ( 121 / 100 )
A = Rs 4840
The Amount after two years = Rs 4840 Now Principal = Rs 4840
Simple interest for last ½ year is = PRT/100 = (4840 × 10 × 1 / 2) / 100 = Rs.242
Amount after 2 ½ year = Rs 4840 + Rs 242 = Rs 5082
C.I = A - P
C.I = Rs 5082 - Rs 4000 = Rs1082
∴ The compound interest is Rs 1082.
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