find the compound interest and amount on Rs. 10,000 for 2 years at the rate of 3% per annum
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Answer:
P = 10000
R = 3%
T = 2 years
SI FOR 1ST YEAR :
SI = p × t × r/100
= 10000 × 3 × 1 / 100
= 300
Amount = p + si = 10000 + 300 = 10300
SI FOR 2ND YEAR:
P = AMOUNT OF 1ST YEAR = 10300
r = 3
t = 1
SI = 10300 × 3 ×1 /100
= 309
AMOUNT = 10300 + 309 = 10609
CI = AMOUNT - PRINCIPAL = 10609 - 10000
= 609
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