Question

Find the compound interest and amount on-

Rs.9600 for 3 yrs at the interest rate of 10% per annum.​

Answer 1

Answer:

a = p (1+r/100)n

where

p is principal

r is rate and

n is time

c.i = a - p

where

a is amount

p is principal

Answer 2

$\bf \: \underline{ Given }\: :$ ↴

$\sf \: Principal \: : \: Rs. 9600$

$\sf \: Rate \: of \: Interest \: : \: 10 \%$

$\sf \: Time \: : \: 3 \: Years.$

$\bf \: \underline{To \: find }\: :$ ↴

$\sf \: We \: have \: to \: find \: the \: Compound \: Interest.$

$\sf \: \bigstar \underline{\: So, \: Let's \: Start \: } \bigstar$

$\sf \: First \: of \: all \: we \: are \: going \: to \: find \: the \: amount..$

$\green{ \underline{\boxed{ \sf \: Amount \: : P \: \bigg(\: 1 + \frac{R}{100} \: \bigg ) ^{n} }}}$

$\sf \: \underline{Putting \: the \: value \: into \: the \: formula.}$

$\sf \: Amount \: : 9600 \: \bigg(\: 1 + \dfrac{10}{100} \: \bigg ) ^{3}$

$\sf \: Amount \: : 9300 \: \bigg(\: \dfrac{11}{10} \bigg ) ^{3}$

$\sf \: Amount \: \rightarrow \:9600 \: \bigg( \: \dfrac{11}{10} \: \times \: \dfrac{11}{10} \: \times \dfrac{11}{10} \bigg)$

$\sf \: Amount \: \rightarrow \: 9600\: \bigg(\dfrac{1331}{1000} \bigg)$

$\sf \: Amount \: \rightarrow \: 96\: \times \: \dfrac{1331}{10}$

$\sf \: Amount \: \rightarrow \: 96\: \times \dfrac{12776}{10}$

$\sf \: Amount \: \rightarrow \: 96\: \times 1277.6$

$\purple{\sf \: Amount \: \rightarrow \: Rs. \: 12777.6}$

$\sf \: \underline{Now, \: we \: will \: find \: the \: Compound \: Interest. }$

$\green{ \underline{ \boxed{ \sf \green{CI = Amount \: - Principal }}}}$

$\sf \: \underline{Putting \: the \: value \: into \: the \: formula.}$

${ \sf {CI = 12777.6\: - \: 9600 }}$

$\purple{{ \sf {CI = Rs. \: 3177.6 }}}$