Question

Find the compound interest and amount on- Rs.9600 for 3 yrs at the interest rate of 10% per annum.​

Answer 1

Answer:

Step-by-step explanation:

ANSWER IS AS BELOW:

Answer 2

Answer :-

• The amount is Rs 12777.6.
• The compound interest is Rs 3177.6.

To find :-

• The compound interest.

Step-by-step explanation :-

• Before finding the compound interest, let's find the amount!

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We know that :-

$\underline{ \boxed{\sf Amount = Principal \Bigg(1 + \dfrac{Rate}{100} \Bigg)^{Time}}}$

Here,

• Principal = Rs 9600.
• Rate = 10% per annum.
• Time = 3 years.

Hence,

$\bf Amount =9600 \bigg(1 + \dfrac{10}{100} \bigg)^{3}$

Reducing 10/100 to it's simplest form,

$\bf Amount =9600 \bigg(1 + \dfrac{1}{10} \bigg)^{3}$

The LCM of 1 and 10 is 10, so adding the fractions using their denominators,

$\bf Amount =9600 \bigg( \dfrac{1 \times 10 + 1 \times 1}{10} \bigg)^{3}$

On simplifying,

$\bf Amount =9600 \bigg( \dfrac{10 + 1}{10} \bigg)^{3}$

Adding 1 to 10,

$\bf Amount =9600 \bigg( \dfrac{11}{10} \bigg)^{3}$

The power here is 3, so removing the brackets and multiplying 11/10 with itself 3 times,

$\bf Amount =9600 \times \dfrac{11}{10} \times \dfrac{11}{10} \times \dfrac{11}{10}$

Let's multiply 11/10 with itself 3 times first.

$\bf Amount =9600 \times \dfrac{11 \times 11 \times 11}{10 \times 10 \times 10}$

On multiplying,

$\bf Amount =9600 \times \dfrac{1331}{1000}$

Cutting off the zeroes,

$\bf Amount =96 \times \dfrac{1331}{10}$

Reducing the numbers,

$\bf Amount =48 \times \dfrac{1331}{5}$

Multiplying 48 with 1331,

$\bf Amount = \dfrac{63888}{5}$

Dividing 63888 by 5,

$\overline{ \boxed{\bf Amount =Rs \: 12777.6}}$

• Hence, the amount is Rs 12777.6.

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• Now, as we know the amount, let's find the compound interest!

We know that :-

$\underline{ \boxed{ \sf CI = Amount - Principal}}$

Here,

• Amount = Rs 12777.6.
• Principal = Rs 9600.

Hence,

$\boxed{\tt CI =12777.6 - 9600}$

$\overline{ \boxed{\tt CI = Rs \: 3177.6}}$

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• Hence, the compound interest is Rs 3177.6.