find the compound interest @ 10% per annum for 2 years on the principle which in 2 years @ 10% per annum yield 200 as simple interest.
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SIMPLE INTEREST= 200
=> P × R × T / 100 = 200
=> P × 10× 2 / 100 = 200
=> P / 5 = 200
=> Principle = Rs 1000
Now,
Amount = P [ 1 + (r /100) ]^t
= 1000 [ 1 + (10/100) ]^2
= 1000 [ 1 + (1/10) ]^2
= 1000 ( 11 / 10)^2
= 1000 × 11 × 11 / 10 × 10
= 10 × 121
= 1210
Compound interest = Amount - Principle
= Rs 1210 - Rs 1000
= Rs 210
=> P × R × T / 100 = 200
=> P × 10× 2 / 100 = 200
=> P / 5 = 200
=> Principle = Rs 1000
Now,
Amount = P [ 1 + (r /100) ]^t
= 1000 [ 1 + (10/100) ]^2
= 1000 [ 1 + (1/10) ]^2
= 1000 ( 11 / 10)^2
= 1000 × 11 × 11 / 10 × 10
= 10 × 121
= 1210
Compound interest = Amount - Principle
= Rs 1210 - Rs 1000
= Rs 210
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