FIND the compound interest at 5 percent per annum for 3 years on the principal , which gives simple interest of rupees 2400 at the same rate and for the same time.
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Answers
S. I =P×R×T/100
2400=P×5×3/100
P=2400×100/5×3
P= 240000/15
P=16000
Now,
Amount = P(1+R/100) n
=16000(1+5/100) 3
= 16000(100+5/100) 3
= 16000(105/100) 3
= 16000×105/100×105/100×105/100
= 16000×21/20×21/20×21/20
= 16000×9261/8000
= 148176000/8000
Amount = RS 18522
Now,
Compound Interest = A-P
= 18522-16000
Compound Interest = RS 2522
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Answer:
S. I =P×R×T/100
2400=P×5×3/100
P=2400×100/5×3
P= 240000/15
P=16000
Now,
Amount = P(1+R/100) n
=16000(1+5/100) 3
= 16000(100+5/100) 3
= 16000(105/100) 3
= 16000×105/100×105/100×105/100
= 16000×21/20×21/20×21/20
= 16000×9261/8000
= 148176000/8000
Amount = RS 18522
Now,
Compound Interest = A-P
= 18522-16000
Compound Interest = RS 2522 ans.