find the compound interest at the rate of 10% per annum for 2 years on the principle which in 2 years at the rate of 10% per annum yields 200 as simple interest
Answers
Answer:
₹210
Step-by-step explanation:
First in case of Simple interest,
Rate = 10% p.a, Time = 2 years, Simple interest = ₹200
Principal = 100*SI/T*R
= 100×200/10×2
= ₹(10×100) = ₹1000
Now for compound interest,
Principal = ₹1000,Rate = 10%p.a, Time = 2 years
Amount = Principal(1+Rate/100)^Time
Thus, Amount = ₹1000(1+10/100)^2
= ₹1000(11/10)^2
= ₹1000×11/10×11/10
= ₹(121×10)
= ₹1210
Hence the compound interest is ₹(1210-1000)= ₹210
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Answer:
210
Step-by-step explanation:
first in case of simple interest
rate = 10%
time years 2 years
simple interest = 200
principles = 100×si/t×R
100×200/10×2
rupees (10×100)=1000
Now for compound interest
amount = principle(1+rate/100)^time
1000 (1+10/100)^2
1000 (11/100)^2
121×10
1210
1210-1000
210
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