Find the compound interest at the rate of 10% per annum for 4 years on the principle which in 4 years at the rate of 4% per annum gives Rs.1600 as simple interest.
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Answered by
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Solution. let The. 1,600 as S.I in four years at the rate of 4% per annum.
p = simple interest multiplied 100/Rate multiplied by Time.
P=1600 multiplied by 100/4 multiplied by 4=Rs.10,000
Now, we have
P=Rs 10,000, R =10% and n = 4
Amount after 4 years =p [1+R/100]^n
=10000 multiplied by [1 + 10/100]^4
=10000 multiplied by [1+1/10]^4
=10000 multiplied by [11/10]^4
= 10000 multiplied by (11/10) (11/10) (11/10) (11/10)
= 14,641
Hence. Compound interest = Rs. 14641 - Rs 10000 = 4,641.
p = simple interest multiplied 100/Rate multiplied by Time.
P=1600 multiplied by 100/4 multiplied by 4=Rs.10,000
Now, we have
P=Rs 10,000, R =10% and n = 4
Amount after 4 years =p [1+R/100]^n
=10000 multiplied by [1 + 10/100]^4
=10000 multiplied by [1+1/10]^4
=10000 multiplied by [11/10]^4
= 10000 multiplied by (11/10) (11/10) (11/10) (11/10)
= 14,641
Hence. Compound interest = Rs. 14641 - Rs 10000 = 4,641.
Anonymous:
thank you
Answered by
2
Answer:
Step-by-step explanation:
SI= p x r x t
1600 = p x 4/100 x 4
p= 1600 x 100/4 x 4
p= 160000/16
p= 10000
CI =
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