Question

find the compound interest if ₹1000 are invested for two years at the rate of 10​

Answer 1

Answer:

Compound Interest = Rs. 210

Step-by-step explanation:

Amount = Principle(1 + Rate of interest/100)to the power of no. of years

             = 1000(1 + 10/100) ^2

             =1000(10+1/10)^2

             =1000(11/10)^2

             =1000×11×11/10×10

             =1210

Compound Interest = Amount  - Principle

                                 =1210 - 1000

                                 =Rs. 210

Answer 2

Answer:-

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★ Given:

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• Principal = ₹1000

• Rate = 10%

• Time = 2 years

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★ To Find:

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• Compound Interest

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★ Formula Used:

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${\pink{\tt{▪︎Amount = Principal{( 1+ \dfrac{Rate}{100})}^{time}}}}$

${\pink{\tt{▪︎Compound\ Interest\ =\ Amount\ -\ Principal}}}$

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★ Solution:

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➢ Finding Amount

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${\tt{Amount = Principal{( 1+ \dfrac{Rate}{100})}^{time}}}$

${\tt{= 1000{( 1 + \dfrac{10}{100})}^{2}}}$

${\tt{= 1000{( \dfrac{11\cancel0}{10\cancel0})}^{2}}}$

${\tt{= 1000 × \dfrac{11}{10} × \dfrac{11}{10}}}$

${\tt{= 10\cancel{00} × \dfrac{121}{1\cancel{00}}}}$

${\tt{=₹1210}}$

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$\boxed{\purple{\tt{\therefore Amount = ₹1210}}}$

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➢ Finding Compound Interest

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${\tt{Compound\ Interest\ =\ Amount\ -\ Principal}}$

${\tt{= 1210 - 1000}}$

${\tt{= ₹210}}$

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$\boxed{\purple{\tt{\therefore Compound\ Interest= ₹210}}}$

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∴ Compound Interest = ₹210