Question

Find the compound interest if ₹8000 is the principal, rate is 10% and time is 3 years.​

Answer 1

Answer:

8000x10%x3/100=2400 rupees is interest

Answer 2

      $\underline{\bold{Answer:}}$

      $C.I = \text{Rs. }2648$

      $\underline{\bold{Step-by-step-explaination:}}$

       $\text{Principal Amount}(P) = \text{Rs. }8000$

       $\text{Rate of Interest}(R) = 10\text{ } o/o$

       $\text{Time}(T) = 3 \text{ years}$

       $\text{We know that, Amount}(A) = \boxed{P(1 + \frac{R}{100})^{T} }$

$\implies \boxed{A = 8000(1 + \frac{10}{100})^{3}}$

       $\text{Simplifying...}$

$\implies \boxed{A = 8000(1 + \frac{1}{10})^{3}}$

       $\text{Simplifying...}$

$\implies \boxed{A = 8000(\frac{11}{10})^{3}}$

       $\text{Simplifying...}$

$\implies \boxed{A = 8000(\frac{11}{10})(\frac{11}{10})(\frac{11}{10})}$

       $\text{Simplifying...}$

$\implies \boxed{A = 8(11)(11)(11)}$

       $\text{Simplifying...}$

$\implies \boxed{A = \text{Rs. }10648}$

       $\text{We know that, Compound Interest}(C.I) = \text{Amount} - \text{Principal}$

$\implies \boxed{C.I = 10648 - 8000}$

       $\text{Simplifying...}$

  $\therefore \text{ }\text{ }\boxed{C.I = \text{Rs. }2648}$