Question

Find the compound interest if principal = rupees 15625 and rate of interest = 4% and time = 3 years

Answer 1

Answer:

p= ₹15625

r= 4%

T= 3 years

S.I= (p×r×t)/100

S.I=(₹15625×4×3)/100

S.I=₹187500/100

S.I=₹1875

A=p+S.I

A=₹15625+₹1875

A=₹189375

C.I=A+p

C.I=₹189375+₹15625

C.I=₹205000

Answer 2

Answer:

Step-by-step explanation:

Given :-

Principle = Rs 15625

Rate of interest = 4 %

Time = 3 years

To Find :-

Compound Interest

Formula to be used :-

$\boxed{\bold{Amount=P(1+\frac{1}{100})^n}}$

$\boxed{\bold{Compound \: Interest = Amount - Principle}}$

Solution :-

Putting all the value, we get

$\sf\implies Amount=P(1+\frac{1}{100})^n$

$\sf\implies Amount=15625(1+\frac{4}{100})^3$

$\sf\implies Amount=15625(\frac{26}{25} })^3$

$\sf\implies Amount=15625\times(\frac{17576}{15625} })$

$\bf\implies Amount=Rs. \: 17576$

Now we will find C.I

$\sf\implies Compound \: Interest = Amount - Principle$

$\sf\implies Compound \: Interest =Rs. \: (17576-15625)$

$\bf\implies Compound \: Interest =Rs. \: 1951$

Hence, the compound interest is Rs. 1951.