Question

find the
compound interest
of 10000at 10 %
per annum for
3 years​

Answer 1

Answer:

Present value =₹ 10000

Interest rate =10% per annum

Time =3 years

To find the amount we have the formula,

Amount (A)=P(1+(r/100))

n

where P is present value, r is rate of interest, n is time in years

Now substituting the values in above formula we get,

∴A=10000(1+10/100)

3

⇒A=10000(11/10)

3

⇒A=121(10)(11)

⇒A=1331(10)

⇒A=₹ 13310

∴ Compound interest =A–P

=13310–10000=₹ 3310

Answer 2

Answer:

13310₹

Step-by-step explanation:

Given :- P. = 10,000₹,

R = 10%,

N = 3 Years

A. = P × ( 1 + R/100)^N

= 10,000 × ( 1+ 10/100 )^3

= 10,000 × 11/10 × 11/10 × 11/10

= 10 × 11^3

= 10 × 1331

= 13310

C.I. = A - P

= 13,310 - 10,000

= 3310

Therefore, the compound interest on 10,000 at 10% p.c.p.a. for 3 years is 3310₹.