Question

find the compound interest of R1000 in 2years.at the rate of 10% per annum​

Answer 1

Step-by-step explanation:

Correct option is A)

Here, Principal P = Rs. 1000

R =10% per annum and n=2 years

∴ Amount after 2 years = P (1+

200

R

)

2n

= Rs. 1000×(1+

200

10

)

2×2

=Rs.1000×(1+

20

1

)

4

=Rs.1000×(

20

21

)

4

= Rs.1000×

20

21

×

20

21

×

20

21

×

20

21

=Rs.1215.50

Hence, compound interest = Amount - Principal

=Rs.1215.50−Rs.1000=Rs.215.50

Answer 2

Answer:

210

Step-by-step explanation:

Principle = p = 1000

Rate of interest = 10%

Time = 2 yrs

$CI = P[(1+i)^n-1]$

$CI = 1,000[(1+0.1)^2-1]$

$CI = 1,000[(1.1)^2-1]$

$[(1.1)^2-1] = 0.21$

$CI = 1,000 * 0.21$

$CI = 210$

Hence , the compound interest of R1000 in 2years.at the rate of 10% per annum is 210