Question

find the compound interest of Rs 18000 @ 10% per annum for the period of 1.5 years when interest is added half yearly​

Answer 1

Step-by-step explanation:

P=18000

R=10÷2

=5

N=1.5x2

=3

A= P (1+R÷100)^N

18000 (1+5÷100)^3

18000 x 1.05^3

18000 x 1.157625

20,837.25

Compound interest = 20837.25 - 18000

2,837.25

Answer 2

Step-by-step explanation:

P=Rs. 18000

R=10%

T=1.5 year

A=P$(1+\frac{R}{200})^{2n}$ for half-yearly compound interest....

A=18000$(1+\frac{10}{200})^3$

A=18000*$\frac{21}{20}* \frac{21}{20}* \frac{21}{20}$

A=18*21*21*21

A=Rs. 20837.25

Therefore, C.I.=Amount - Principal

C.I.=20837.25-18000

Therefore, C.I.=2837.25 (Ans.)

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