Question

find the compound interest of rs 4400 at rate of interest of 10% p.a. with intrest reckoned half - year for a year​

Answer 1

Answer:

Explanation:

Principal = P =  4400

Rate Of Interest = R = 10% per annum

Time period = t = 1 year

The interest is compounded every half year

then. n = 2

COMPOUND INTEREST FORMULA:

$A = P(1 + \frac{R}{n})^{nt}$

then, putting values into the formula

A = 4400(1 + 10/2)ˆ(2*1)

A = 4400(1+ 5)ˆ(2)

A = 4400(36)

A = 158400

Then,

Compound Interest = A - P = 1,54,000

Answer 2

Answer:

here ur answer

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thnx