Find the compound interest of rs2000 in 2 years at the rate of 5% p.a. pls solve this in a page and send a image. pls .will mark you brainliest. pls
Answers
Answered by
4
Hey dear!
Here is yr answer......
Given,
P = 2000
T = 2 yrs (n)
R = 5% = 5/100 = 0.05
C. I. = p(1+r/100)^n
= 2000(1+0.05/100)^2
= 2000(100+0.05/100)^2
= 2000(10010.0025 / 10000)
= 10010.0025/5
= 2002.0005
Hope it hlpz...
Here is yr answer......
Given,
P = 2000
T = 2 yrs (n)
R = 5% = 5/100 = 0.05
C. I. = p(1+r/100)^n
= 2000(1+0.05/100)^2
= 2000(100+0.05/100)^2
= 2000(10010.0025 / 10000)
= 10010.0025/5
= 2002.0005
Hope it hlpz...
arjunsengupta16:
ok
C. I = p (1+r/n)^(nt)
then
= 2000(1+5/2)^(2×2)
= 2000(4+5/2)4
= 2000(9/4)^4
= sorry
= 2000(9/2)^4
do u know c.i
? atleast
Answered by
3
Hi Friend !!!
Here is ur answer !!!
P = ₹ 2000
T = 2
R = 5
C. I = p(1+r/n)^n
= 2000(1+5/2)^2
= 2000(2+5/2)^2
= 2000(7/2)^2
= 2000×49/4
= 500×49
= ₹ 24,500
Hope it helps u
Here is ur answer !!!
P = ₹ 2000
T = 2
R = 5
C. I = p(1+r/n)^n
= 2000(1+5/2)^2
= 2000(2+5/2)^2
= 2000(7/2)^2
= 2000×49/4
= 500×49
= ₹ 24,500
Hope it helps u
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