Math, asked by niranjan8657, 1 year ago

find the compound interest of rupees 5000 @ 10% per annum compounded semi annually for 1.5 years​

Answers

Answered by rainha
41

Answer:

788.12

Step-by-step explanation:

time double and rate half in calculating interest semi annually

5000(1+5/100)^3

=5000(1+1/20)^3

=5000(21/20)^3

=5000x9261/8000

=5788.12(app.)

compound interest=5788.12-5000=788.12

Answered by pinquancaro
37

The compound interest is Rs.788.125.

Step-by-step explanation:

Given : Rupees 5000 @ 10% per annum compounded semi annually for 1.5 years​.

To find : The compound interest ?

Solution :

The compound interest formula is CI=A-P

Where, A = P(1+\frac{r}{n})^{nt}

Here, Principal p= Rs.5000

Rate of interest r= 10% =0.1

No. of compounds per year = n = 2

Time t= 1.5 year

Substitute the values,

A = 5000(1+\frac{0.1}{2})^{ 2\times 1.5}

A = 5000(1.05)^{ 3}

A = 5000\times 1.157625

A=Rs.5788.125

Compound interest = Amount - Principal

Compound interest = 5788.125-5000

Compound interest = Rs.788.125

Therefore, the compound interest is Rs.788.125.

#Learn more

Find the Compound Interest on Rs.1,00,000 compounded semi annually for 1.5 years at the rate of 8% per annum.

brainly.in/question/2360471

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